A Calculadora da taxa de ventilação do desaerador helps determine the amount of non-condensable gases, primarily oxigênio e dióxido de carbono, that must be vented from feedwater in a deaerator system. Deaerators are used in poder plants, boiler systems, and industrial steam applications to remove dissolved gases from feedwater to prevent corrosion and improve efficiency.
Calculando o vent rate, os operadores podem:
- Ensure the deaerator is functioning correctly.
- Optimize oxygen removal efficiency.
- Reduce corrosion-related maintenance costs.
- Melhorar o longevidade and efficiency of boilers and steam systems.
Formula of Deaerator Vent Rate Calculator
A vent rate is determined by the amount of non-condensable gases removed from the feedwater using the following formula:
Vent Rate (kg/hr) = (Feedwater Flow × Oxygen Content) / Desired Oxygen Removal Efficiency
Onde:
- Feedwater Flow (kg/hr or lb/hr) = O taxa de fluxo de massa of the incoming water.
- Oxygen Content (kg/kg or ppm) = The dissolved oxygen content in the feedwater before deaeration.
- Desired Oxygen Removal Efficiency (%) = The fraction of oxygen to be remove, typically expressed as a percentage.
This formula helps determine how much gas needs to be vented to achieve the desired deaeration level in a given system.
Deaerator Vent Rate Reference Table
Abaixo está uma tabela de referência for common deaeration scenarios:
| Feedwater Flow (kg/hr) | Initial Oxygen Content (ppm) | Desired Removal Efficiency (%) | Required Vent Rate (kg/hr) |
|---|---|---|---|
| 10,000 | 8 | 99.5% | 0.04 |
| 20,000 | 6 | 99.0% | 0.12 |
| 30,000 | 7 | 99.5% | 0.11 |
| 50,000 | 5 | 98.0% | 0.25 |
| 100,000 | 4 | 99.8% | 0.08 |
Esta tabela fornece estimated vent rates to help engineers and boiler operators avaliar rapidamente deaerator performance.
Example of Deaerator Vent Rate Calculator
Vamos dizer um usina is deaerating 50,000 kg/hr of feedwater, e o initial oxygen content na água está 6 ppm (partes por milhão). O alvo oxygen removal efficiency is 99.5%.
- Converter ppm to kg/kg:
- Como 1 ppm = 1 mg/L,
- 6 ppm = 6 mg/kg = 0.000006kg/kg.
- Apply the formula:Vent Rate = (50,000 kg/hr × 0.000006 kg/kg) / 0.995
Vent Rate = (0.3 kg/hr) / 0.995
Vent Rate ≈ 0.302 kg / hr
Isso significa que o deaerator must vent 0.302 kg/hr of gases para alcançar o desired oxygen removal efficiency.
Perguntas frequentes mais comuns
Venting is essential to remove dissolved oxygen and carbon dioxide from feedwater, which helps prevenir corrosão in boilers and steam turbines.
If the vent rate is too low, oxygen may not be fully remove, levando a corrosion in the steam system and reducing boiler lifespan.
Yes, excessive venting can waste energy and steam, reducing the efficiency of the deaerator system and increasing operating costs.