The Farads to Joules Calculator helps users determine the amount of energy stored in a capacitor based on its capacitance and the voltage applied. This is important in electrical and electronics applications where understanding the energy potential of capacitors is essential for safety, performance, and design efficiency. Whether you are building an energy storage device, designing a timing circuit, or testing supercapacitors, this tool makes the calculation quick, simple, and reliable.
This calculator is part of the Electrical Energy Conversion Tools and is particularly useful in battery alternatives, regenerative energy systems, and capacitor banks used in power electronics.
formula of Farads To Joules Calculator
Energy (J) = (1/2) × C × V²
Where:
Energy = energy stored in joules (J)
C = capacitance in farads (F)
V = voltage across the capacitor (in volts, V)
This equation calculates how much electrical energy is stored in a capacitor. The value is derived from the physical behavior of capacitors in storing and releasing electrical energy through electric fields.
Common Capacitor Energy Values Reference Table
Capacitance (F) | Voltage (V) | Stored Energy (J) |
---|---|---|
1 F | 5 V | 12.5 J |
10 F | 2.7 V | 36.45 J |
50 F | 3 V | 225 J |
100 F | 2.5 V | 312.5 J |
500 F | 2.7 V | 1822.5 J |
3000 F | 2.7 V | 10935 J |
This table gives a quick overview of stored energy based on commonly used capacitance and voltage values. It helps people estimate the energy potential without doing manual math each time.
Example of Farads To Joules Calculator
Let’s say you have a capacitor with a capacitance of 1500 F and a voltage of 2.5 V.
Step 1: Use the formula
Energy (J) = (1/2) × C × V²
Energy = 0.5 × 1500 × (2.5)² = 4687.5 J
So, the capacitor stores 4687.5 joules of energy when charged to 2.5 volts.
Most Common FAQs
It tells you how much electrical energy the capacitor can hold and deliver. This helps determine whether it can power your circuit or system effectively.
Yes, this formula is especially useful for supercapacitors, which store much more energy than regular capacitors.
Yes. Since voltage is squared in the formula, even a small increase in voltage greatly increases the stored energy.